Mathematics is a complex but interesting subject. In the beginning, you will deal with some simple problems, but when you reach to higher classes, complexity will increase. You will learn about topics where instead of numbers you will see letters. We are talking about algebra where letters indicate a constant number replaces numbers. An algebra equation can also include complex numbers, real numbers, matrices, and vectors as well. In most of the equation, you will see X, Y, A, B, C which are common used letters. This type of equation indicates a scale that should be balanced which means whatever you do on one side should also be done on another side. This is to balance the scale. Algebra formulas are used to solve the algebra problem. With the use of such formulas, one can easily find out the answer to the given question. There are few rules that an algebra equation follow, and by observing them, you can easily identify the equation.
Example 5x+4=12 Here a nonzero coefficient is multiplied by x. There is also an equal sign as well hence the above problem fulfills the above requirements, so the equation is true. To solve it, just take the number 4 to righthand side by changing its sign. 5x=124 Subtract the numbers on R.H.S and divide the result by 5; you will get the value of x. X=8/5 It was a simple problem, but the higher level of mathematics contains complex formulas that can be solved using formulas. Let us learn about those formulas with examples Many more formulas are there but the above one is common, and students should remember this one only. If you learn them, you can easily solve your algebra homework. Here is a solved example is given to make you understand how to use the formula.
Question:6²3² Solution: to solve this problem, use the above formula. Put the value of a=6 and b=3 so that the equation will become =(ab) (a+b) =(63)(6+4) = 3*12 =30 In this way, you can use the above formula. Students will learn some properties as well when they reach to higher classes. These properties are very useful for solving a problem. Some are given below: Distributive property a(b+c)=a*b+a*c Commutative property a + b = b+a a*b = b*a Associative property a + (b+c) = (a+b) + c a * (b*c) = (a*b) * c Additive property a+0=a Multiplicative property a*1=a Students can easily solve problems using these properties. To understand better, you can also take the help from algebra software. Such software explains the solution of any problem step by step. These are the very good way to learn how to use a particular formula. You can solve any problem from your textbook and use software to get its solution. In this way, anyone can master algebra and get good marks in the examination.
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